fill in the blank 1 point
determine the slope. (enter a number only!)
1. if the slope # of one line is -12, then the slope # for a parallel line is
2. if the slope # of one line is 6/11, then the slope # for a perpendicular line is
3. if the slope # of one line is 2/9, then the slope # of a parallel line is
4. if the slope # of one line is -3/14, then the slope # of a perpendicular line is

Question

Accepted Answer

### Sub - Question 1
# Explanation:
## Step1: Recall slope of parallel lines
Parallel lines have equal slopes.
## Step2: Apply the rule
Given one line has slope - 12, so the parallel line also has slope - 12.
# Answer: -12

### Sub - Question 2
# Explanation:
## Step1: Recall slope of perpendicular lines
If two lines are perpendicular, the product of their slopes is - 1. Let the slope of the given line be $m_1=\frac{6}{11}$ and the slope of the perpendicular line be $m_2$. Then $m_1\times m_2=- 1$.
## Step2: Solve for $m_2$
$m_2=\frac{-1}{m_1}=\frac{-1}{\frac{6}{11}}=-\frac{11}{6}$
# Answer: $-\frac{11}{6}$

### Sub - Question 3
# Explanation:
## Step1: Recall slope of parallel lines
Parallel lines have equal slopes.
## Step2: Apply the rule
Given one line has slope $\frac{2}{9}$, so the parallel line also has slope $\frac{2}{9}$.
# Answer: $\frac{2}{9}$

### Sub - Question 4
# Explanation:
## Step1: Recall slope of perpendicular lines
If two lines are perpendicular, the product of their slopes is - 1. Let the slope of the given line be $m_1 =-\frac{3}{14}$ and the slope of the perpendicular line be $m_2$. Then $m_1\times m_2=-1$.
## Step2: Solve for $m_2$
$m_2=\frac{-1}{m_1}=\frac{-1}{-\frac{3}{14}}=\frac{14}{3}$
# Answer: $\frac{14}{3}$

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QUESTION IMAGE

Question

Explanation:

Sub - Question 1

Step1: Recall slope of parallel lines

Step2: Apply the rule

Step1: Recall slope of perpendicular lines

Step2: Solve for \(m_2\)

Step1: Recall slope of parallel lines

Step2: Apply the rule

Answer:

Sub - Question 2