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5 fill in the blank 1 point fill in the correct coefficients for the eq…

Question

5 fill in the blank 1 point fill in the correct coefficients for the equation below by just typing the number. do not add any spaces, do not spell out the number. (if there is not a coefficient needed, simply write a \1\ so that it shows there is just one of that molecule) type your answer_ oxygen + type your answer_ glucose ⇒ type your answer_ water + type your answer_ carbon dioxide + type your answer_ atp

Explanation:

The problem is about balancing the cellular respiration equation. The correct balanced equation for cellular respiration is \( \text{C}_6\text{H}_{12}\text{O}_6 + 6\text{O}_2
ightarrow 6\text{CO}_2 + 6\text{H}_2\text{O} + \text{ATP} \) (but for the coefficients in the given format, we consider the reactants and products as per the blanks. Wait, actually, the equation here seems to be written in reverse? Wait, no, maybe a typo. Wait, the standard cellular respiration is Glucose + Oxygen → Carbon Dioxide + Water + ATP. So the correct coefficients are: for Oxygen (reactant) when Glucose is 1, Oxygen is 6; Glucose is 1; Water is 6; Carbon Dioxide is 6; ATP is a variable but in the balanced equation for the molecules, let's correct the equation structure.

Wait, the given equation in the problem is: [Blank] Oxygen + [Blank] Glucose → [Blank] Water + [Blank] Carbon Dioxide + [Blank] ATP. Wait, no, the arrow is from Oxygen + Glucose to Water + Carbon Dioxide + ATP? No, that's reverse. Wait, maybe it's a typo and should be Glucose + Oxygen → Carbon Dioxide + Water + ATP. Let's assume the correct equation is Glucose (\( \text{C}_6\text{H}_{12}\text{O}_6 \)) + Oxygen (\( \text{O}_2 \)) → Carbon Dioxide (\( \text{CO}_2 \)) + Water (\( \text{H}_2\text{O} \)) + ATP.

Balancing the equation:

  • Glucose: 1 (so coefficient for Glucose is 1)
  • Oxygen: To balance O and H and C. Let's balance C first: Glucose has 6 C, so CO₂ needs 6. Then H: Glucose has 12 H, so H₂O needs 6 (62=12). Then O: On right, CO₂ has 62=12, H₂O has 6*1=6, total O on right (excluding ATP which has variable) is 18. On left, Glucose has 6 O, so O₂ needs (18-6)/2 = 6. So O₂ coefficient is 6, Glucose is 1, H₂O is 6, CO₂ is 6, and ATP is produced in large amounts but in the equation for the molecule coefficients (ignoring ATP's energy aspect), the coefficients for the reactants and products (molecules) are:

So the equation should be: 6 Oxygen + 1 Glucose → 6 Water + 6 Carbon Dioxide + (many) ATP, but since the problem asks for coefficients, let's list them in the order of the blanks:

First blank (Oxygen coefficient): 6

Second blank (Glucose coefficient): 1

Third blank (Water coefficient): 6

Fourth blank (Carbon Dioxide coefficient): 6

Fifth blank (ATP coefficient): Since ATP is not a molecule with fixed coefficient in the same way (it's energy), but the problem says "if no coefficient needed, write 1". But in the balanced equation for the molecules, ATP is a product of the reaction, and its number depends on the type of respiration, but for the sake of the problem (maybe a simplified version), we can assume 1 or the actual, but in the standard equation, the coefficients for the molecules (O₂, C₆H₁₂O₆, H₂O, CO₂) are 6,1,6,6. ATP is not a molecule with a fixed coefficient in the same stoichiometric sense as the others, but since the problem includes it, maybe we put 1 (or the actual, but usually, the equation for the reaction is \( \text{C}_6\text{H}_{12}\text{O}_6 + 6\text{O}_2
ightarrow 6\text{CO}_2 + 6\text{H}_2\text{O} + 36\text{ATP} \) (approx), but the problem might be simplifying. However, the blanks are in the order:

[Oxygen coefficient] Oxygen + [Glucose coefficient] Glucose → [Water coefficient] Water + [Carbon Dioxide coefficient] Carbon Dioxide + [ATP coefficient] ATP

So based on the standard balanced equation (simplified for molecules, ignoring ATP's exact number as it's energy), the coefficients are:

Oxygen: 6

Glucose: 1

Water: 6

Carbon Dioxide: 6

ATP: Let's assume 1 (or the problem might accept 1, as ATP is a product but not a molecule with a fixed stoichi…

Answer:

6, 1, 6, 6, 1 (in the order of the blanks: Oxygen, Glucose, Water, Carbon Dioxide, ATP)