Question

k(x) = \sqrt3{x + 1} + 5\
find k(-9).

Explanation:

Step1: Substitute $x=-9$ into $k(x)$

$k(-9) = \sqrt[3]{-9 + 1} + 5$

Step2: Simplify the radicand

$k(-9) = \sqrt[3]{-8} + 5$

Step3: Evaluate the cube root

$k(-9) = -2 + 5$

Step4: Calculate the final sum

$k(-9) = 3$

Answer:

3