Question

find the binomial distribution for flipping a coin 3 times, where \heads\ is a success. p(k successes) = _nc_kp^k(1 - p)^(n - k) p(0 successes) = _3c_0(0.5)^0(0.5)^3 = 0.125 p(1 success) = 0.375 p(2 successes) = 0.375 p(3 successes) = 0125 → 0.125 complete what is the probability that you will get \heads\ no more than once out of 3 flips? p(0 successes) + p(1 success) =

Explanation:

Step1: Recall given probabilities

We know $P(0\text{ successes}) = 0.125$ and $P(1\text{ success})=0.375$.

Step2: Calculate sum

We need to find $P(0\text{ successes})+P(1\text{ success})$. So, $0.125 + 0.375$.

Answer:

$0.5$