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Question
find the inverse function. f(x) = 3x - 1 f⁻¹(x) = (x + ?) / ?
Step1: Replace \( f(x) \) with \( y \)
\( y = 3x - 1 \)
Step2: Swap \( x \) and \( y \)
\( x = 3y - 1 \)
Step3: Solve for \( y \)
First, add 1 to both sides: \( x + 1 = 3y \)
Then, divide both sides by 3: \( y = \frac{x + 1}{3} \)
So the inverse function \( f^{-1}(x)=\frac{x + 1}{3} \)
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The numerator's box should be 1 and the denominator's box should be 3. So \( f^{-1}(x)=\frac{x + \boldsymbol{1}}{\boldsymbol{3}} \)