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Question
find the inverse function in slope-intercept form (mx+b):
$f(x) = -dfrac{2}{3}x - 12$
Step1: Replace \( f(x) \) with \( y \)
\( y = -\frac{2}{3}x - 12 \)
Step2: Swap \( x \) and \( y \)
\( x = -\frac{2}{3}y - 12 \)
Step3: Solve for \( y \)
First, add 12 to both sides: \( x + 12 = -\frac{2}{3}y \)
Then, multiply both sides by \( -\frac{3}{2} \): \( y = -\frac{3}{2}(x + 12) \)
Expand the right side: \( y = -\frac{3}{2}x - 18 \)
Step4: Replace \( y \) with \( f^{-1}(x) \)
\( f^{-1}(x) = -\frac{3}{2}x - 18 \)
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\( f^{-1}(x) = -\frac{3}{2}x - 18 \)