Question

find the length of side x to the nearest tenth.
(image of a right isosceles triangle with hypotenuse √11 and one leg labeled x)
answer attempt 1 out of 2
x = blank submit a

Explanation:

Step1: Identify triangle properties

This is an isosceles right triangle: the two legs are equal ($x$ each), hypotenuse is $\sqrt{11}$.

Step2: Apply Pythagorean theorem

$$x^2 + x^2 = (\sqrt{11})^2$$

Step3: Simplify the equation

$$2x^2 = 11$$
$$x^2 = \frac{11}{2}$$

Step4: Solve for $x$

$$x = \sqrt{\frac{11}{2}} = \frac{\sqrt{22}}{2} \approx 2.3$$

Answer:

$2.3$