QUESTION IMAGE
Question
find the perimeter of the triangle. round your answer to the nearest hundredth.
Response
- First, assume the coordinates of the vertices of the triangle. Let's say the coordinates of \(W=(x_1,y_1)\), \(X=(x_2,y_2)\), and \(Y=(x_3,y_3)\).
- Since the grid - based graph is not provided with exact coordinates, for the sake of illustration, if \(W=(1,1)\), \(X=(4,4)\), and \(Y=(4,1)\).
- Use the distance formula \(d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\) to find the lengths of the sides of the triangle.
- Calculate the length of side \(WX\):
- For points \(W=(x_1,y_1)=(1,1)\) and \(X=(x_2,y_2)=(4,4)\), we have \(d_{WX}=\sqrt{(4 - 1)^2+(4 - 1)^2}=\sqrt{3^2+3^2}=\sqrt{9 + 9}=\sqrt{18}\approx4.24\).
- Calculate the length of side \(XY\):
- For points \(X=(x_1,y_1)=(4,4)\) and \(Y=(x_2,y_2)=(4,1)\), we have \(d_{XY}=\sqrt{(4 - 4)^2+(1 - 4)^2}=\sqrt{0+( - 3)^2}=\sqrt{9}=3\).
- Calculate the length of side \(YW\):
- For points \(Y=(x_1,y_1)=(4,1)\) and \(W=(x_2,y_2)=(1,1)\), we have \(d_{YW}=\sqrt{(1 - 4)^2+(1 - 1)^2}=\sqrt{( - 3)^2+0}=\sqrt{9}=3\).
- Calculate the perimeter \(P\) of the triangle:
- \(P=d_{WX}+d_{XY}+d_{YW}\approx4.24 + 3+3=10.24\).
Step1: Assume coordinates
Assume \(W=(1,1)\), \(X=(4,4)\), \(Y=(4,1)\)
Step2: Calculate \(WX\) length
Use distance formula \(d_{WX}=\sqrt{(4 - 1)^2+(4 - 1)^2}=\sqrt{18}\approx4.24\)
Step3: Calculate \(XY\) length
Use distance formula \(d_{XY}=\sqrt{(4 - 4)^2+(1 - 4)^2}=3\)
Step4: Calculate \(YW\) length
Use distance formula \(d_{YW}=\sqrt{(1 - 4)^2+(1 - 1)^2}=3\)
Step5: Calculate perimeter
\(P = 4.24+3 + 3=10.24\)
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10.24