Question

find the poh of a solution containing 0.45 m of the strong base naoh.
13.65
15.13
0.35
−1.13

Explanation:

Step1: Identify $[OH^-]$ concentration

Since $NaOH$ is a strong base and dissociates completely as $NaOH
ightarrow Na^+ + OH^-$, the concentration of $OH^-$ ions $[OH^-]=0.45\ M$.

Step2: Calculate pOH

The formula for pOH is $pOH = -\log[OH^-]$. Substituting $[OH^-]=0.45$ into the formula, we get $pOH=-\log(0.45)$.
$pOH = 0.35$ (using a calculator).

Answer:

C. 0.35