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1) find x round to the nearest tenth.

Question

  1. find x round to the nearest tenth.

Explanation:

Step1: Use sine function

In a right - triangle, $\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}$. Here, $\theta = 71^{\circ}$, the opposite side to the angle $\theta$ is 15 and the hypotenuse is $x$. So, $\sin71^{\circ}=\frac{15}{x}$.

Step2: Solve for $x$

We can rewrite the equation as $x=\frac{15}{\sin71^{\circ}}$. Since $\sin71^{\circ}\approx0.9455$, then $x=\frac{15}{0.9455}\approx15.9$.

Answer:

$15.9$