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find the value of x. 18 12 $x = ?\\sqrt{\\quad}$

Question

find the value of x.
18
12
$x = ?\sqrt{\quad}$

Explanation:

Step1: Apply Pythagorean theorem

$x^2 = 18^2 + 12^2$

Step2: Calculate squared terms

$x^2 = 324 + 144 = 468$

Step3: Simplify the square root

$x = \sqrt{468} = \sqrt{36 \times 13} = 6\sqrt{13}$

Answer:

$6\sqrt{13}$