Question

find the values of x and y so that the quadrilateral is a parallelogram.$(3y + 15)^{circ}$$(7x - 11)^{circ}$$(5x + 29)^{circ}$$(5y - 9)^{circ}$$x = square$$y = square$calculatorhighlighterneed help?

Explanation:

Step1: Set equal opposite angles

$5x + 29 = 7x - 11$

Step2: Solve for x

$29 + 11 = 7x - 5x$
$40 = 2x$
$x = \frac{40}{2} = 20$

Step3: Set equal opposite angles

$3y + 15 = 5y - 9$

Step4: Solve for y

$15 + 9 = 5y - 3y$
$24 = 2y$
$y = \frac{24}{2} = 12$

Answer:

$x = 20$; $y = 12$