Question

the first ionization energy for sodium is 496 kj/mol. which equation represents the first ionization energy for a sodium atom?1. $\text{na}^{2+}
ightarrow \text{na}^+ + 2\text{e}^- + 992 \text{kj}$2. $\text{na}
ightarrow \text{na}^+ + \text{e}^- + 496 \text{kj}$3. $992 \text{kj} + \text{na}^{2+}
ightarrow \text{na}^+ + \text{e}^-$4. $496 \text{kj} + \text{na}
ightarrow \text{na}^+ + \text{e}^-$

Explanation:

First ionization energy is the energy required to remove one valence electron from a neutral gaseous atom to form a +1 gaseous ion. The process absorbs energy, so the energy is written as a reactant. Sodium's first ionization energy is 496 kJ/mol, so this energy is added to the neutral Na atom to produce Na⁺ and an electron.

Answer:

496 kJ + Na→Na⁺ + e⁻