Question

a flask contains 0.410 mol of liquid bromine, br₂. determine the number of bromine molecules present in the flask. express your answer numerically in molecules. view available hint(s)

Explanation:

Step1: Recall Avogadro's number

Avogadro's number is \( 6.022\times10^{23} \) molecules/mol, which relates moles to number of molecules. The formula to find number of molecules (\( N \)) is \( N = n\times N_A \), where \( n \) is moles and \( N_A \) is Avogadro's number.

Step2: Substitute values

Given \( n = 0.410 \) mol and \( N_A = 6.022\times10^{23} \) molecules/mol. So, \( N=0.410\space mol\times6.022\times10^{23}\space molecules/mol \).
Calculate \( 0.410\times6.022\times10^{23}= 0.410\times6.022\times10^{23}\approx2.46902\times10^{23} \) molecules.

Answer:

\( 2.47\times10^{23} \) (or more precisely \( 2.46902\times10^{23} \)) molecules