Question

formula 10 points
complete the following conversion. you should show the work on your own paper to be certain you have the correct choice of the two conversion factors. round your answer to the hundredths place.
how many moles is 300.77 grams of iodine (i)?
answer

Explanation:

Step1: Recall the molar mass of iodine (I)

The molar mass of iodine (I) is approximately \( 126.90 \, \text{g/mol} \). This value is found on the periodic table, representing the mass of one mole of iodine atoms.

Step2: Use the formula for moles (\( n = \frac{m}{M} \))

The formula to calculate the number of moles (\( n \)) is \( n = \frac{m}{M} \), where \( m \) is the mass in grams and \( M \) is the molar mass in grams per mole. Here, \( m = 300.77 \, \text{g} \) and \( M = 126.90 \, \text{g/mol} \). Plugging in the values:
\( n = \frac{300.77}{126.90} \)

Step3: Perform the division

Calculating \( \frac{300.77}{126.90} \approx 2.3699 \)

Step4: Round to the hundredths place

Rounding \( 2.3699 \) to the hundredths place (two decimal places) gives \( 2.37 \).

Answer:

\( 2.37 \)