Question

free body diagram 1 numeric 1 point what is the magnitude (size) of the net (total) force experienced by the object? report your answer in newtons to 1 decimal place. your permitted error is ±0.1 n. do not use negatives regardless of the direction of the force - that will be answered in the next question. do not insert units into the answer field, only insert the number. answer

Explanation:

Step1: Analyze horizontal forces

The horizontal forces are $F_{x1} = 76N$ and $F_{x2}=- 76N$. The net - horizontal force $F_x=F_{x1}+F_{x2}=76 + (-76)=0N$.

Step2: Analyze vertical forces

The vertical forces are $F_{y1}=126N$ and $F_{y2} = 60N$. The net - vertical force $F_y=F_{y1}-F_{y2}=126 - 60 = 66N$.

Step3: Calculate net force

Since $F_x = 0N$ and $F_y=66N$, the magnitude of the net force $F=\sqrt{F_x^{2}+F_y^{2}}=\sqrt{0^{2}+66^{2}} = 66.0N$.

Answer:

66.0