Question

fy the expression completely if possible.
\\(\frac{2x^2 + 18x}{x^2 + 9x}\\)

Explanation:

Step1: Factor numerator and denominator

Factor out common terms. For the numerator \(2x^{2}+18x\), factor out \(2x\) to get \(2x(x + 9)\). For the denominator \(x^{2}+9x\), factor out \(x\) to get \(x(x + 9)\). So the expression becomes \(\frac{2x(x + 9)}{x(x + 9)}\).

Step2: Cancel common factors

Assuming \(x
eq0\) and \(x
eq - 9\) (to avoid division by zero), we can cancel out the common factors \(x\) and \((x + 9)\) from the numerator and the denominator. After canceling, we are left with \(2\).

Answer:

\(2\) (with the restrictions \(x
eq0\) and \(x
eq - 9\))