QUESTION IMAGE
Question
geometry x unit 2: proof practice
- given: b is between a and c. ab = 9 bc = 7 prove: 16 = ac
proof statements
- b is between a and c.
- ab = 9, bc = 7
- ab + bc = ac
- 9 + 7 = ac
- 16 = ac
reasons
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given: rv bisects ∠srt. ∠3 ≅ ∠1
Step1: Given information
Given that \(B\) is between \(A\) and \(C\), \(AB = 9\), \(BC=7\)
Step2: Use segment - addition postulate
By the segment - addition postulate, if \(B\) is between \(A\) and \(C\), then \(AB + BC=AC\). Substituting the given values: \(9 + 7=AC\)
Step3: Calculate \(AC\)
\(9+7 = 16\), so \(AC = 16\)
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- Given
- Given
- Segment - addition postulate
- Substitution property of equality
- Simplification (or arithmetic)