Question

give the electron configuration for the element given. use the noble gas core preceding for the inner electrons. w:

Explanation:

Step1: Determine the atomic number of W (Tungsten)

Tungsten has an atomic number of 74. The noble gas before tungsten is Xenon (Xe) with atomic number 54.

Step2: Calculate the remaining electrons

Subtract the atomic number of Xe from that of W: \( 74 - 54 = 20 \) electrons to distribute in the outer shells.

Step3: Determine the electron configuration for the remaining electrons

Tungsten is a transition metal in the d - block. The electron configuration for the remaining 20 electrons follows the order of filling orbitals. The electron configuration of W using the noble gas core (Xe) is: \( [Xe] 4f^{14} 5d^{4} 6s^{2} \) (Note: There is a special case in tungsten where one electron from the 6s orbital moves to the 5d orbital to make the 5d orbital more stable, but the common electron configuration using noble gas core is \( [Xe] 4f^{14} 5d^{4} 6s^{2} \))

Answer:

\( [Xe] 4f^{14} 5d^{4} 6s^{2} \)