Question

give the noble gas abbreviated electron configuration for sulfur using the box orbital method. s has 1 electrons. the noble gas in brackets represents 2 of the total of 3 core electrons. 4 35 36

Explanation:

Step1: Determine number of electrons in sulfur

Sulfur (S) has atomic number 16, so it has 16 electrons.

Step2: Identify noble - gas core

The noble gas before sulfur is neon (Ne) which has 10 electrons. The noble - gas in brackets represents 10 of the total 10 core electrons.

Step3: Write the remaining electron configuration

After the [Ne] core, we have 6 remaining electrons. These go into the 3s and 3p orbitals. The 3s orbital fills first with 2 electrons (paired) and then the 3p orbital gets 4 electrons. According to Hund's rule, the 3p electrons first fill each of the three 3p orbitals singly and then pair up. So the remaining configuration is 3s$^2$3p$^4$.
The noble - gas abbreviated electron configuration for sulfur is [Ne]3s$^2$3p$^4$. In box - orbital notation:
For the 3s orbital, it is a single box with two electrons of opposite spin (arrow up and arrow down), and for the 3p orbitals, there are three boxes with the first two boxes having one electron (arrow up) and the third box having two electrons (arrow up and arrow down).

Answer:

1. 16
2. 10
3. 10
4. Ne
5. s$^2$
6. p$^4$ (with box - orbital representation: for 3s: c, for 3p: dd)