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given: abcd is a parallelogram, \\(\\overline{ac}\\) bisects \\(\\angle…

Question

given: abcd is a parallelogram, \\(\overline{ac}\\) bisects \\(\angle bcd\\) and \\(\overline{db}\\) bisects \\(\angle abc\\). prove: \\(\overline{ac} \perp \overline{bd}\\). step statement reason 1 abcd is a parallelogram \\(\overline{ac}\\) bisects \\(\angle bcd\\) \\(\overline{db}\\) bisects \\(\angle abc\\) given 2 \\(\angle cbd \cong \angle abd\\) an angle bisector divides an angle into two congruent angles 3 \\(\overline{bc} \parallel \overline{ad}\\) opposite sides of a parallelogram are parallel 4 \\(\angle bca \cong \angle cad\\) parallel lines cut by a transversal form congruent alternate interior angles 5 \\(\angle dca \cong \angle bca\\) an angle bisector divides an angle into two congruent angles 6 \\(\angle cad \cong \angle dca\\) transitive property 7 \\(\overline{ad} \cong \overline{cd}\\) in a triangle, sides opposite of congruent angles are congruent try type of statement \\(\overline{xy} \cong \overline{wz}\\) \\(\angle x \cong \angle y\\) \\(\triangle xyz \cong \triangle tuv\\) \\(\overline{xy} \parallel \overline{wz}\\) \\(\overline{xy} \perp \overline{wz}\\) classify a triangle \\(\angle x\\) and \\(\angle y\\) are complementary/supplementary \\(\angle x\\) is a right angle \\(\overline{xy}\\) bisects \\(\angle x\\) \\(\overline{xy}\\) bisects \\(\overline{wz}\\) \\(xy = \frac{1}{2}wz\\) (or \\(2wz\\)) \\(m\angle x = \frac{1}{2}m\angle y\\) (or \\(2m\angle y\\)) note: \\(bd\\) and \\(\overline{ac}\\) are segments. you m e in order to submit.

Explanation:

Step1: Identify ABCD as rhombus

Since $AD \cong CD$ (Step7) and $ABCD$ is a parallelogram, a parallelogram with adjacent congruent sides is a rhombus.

Step2: Use rhombus diagonal property

In a rhombus, the diagonals are perpendicular to each other.

Answer:

$\overline{AC} \perp \overline{BD}$

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To complete the proof table, the missing steps (after Step7) would be:

Step8:

Statement: $ABCD$ is a rhombus
Reason: A parallelogram with a pair of adjacent congruent sides is a rhombus

Step9:

Statement: $\overline{AC} \perp \overline{BD}$
Reason: The diagonals of a rhombus are perpendicular