Question

given the function $f(x) = 3x^2 - 8x + 1$. calculate the following values:
$f(-2) = $
$f(-1) = $
$f(0) = $
$f(1) = $
$f(2) = $
question help: video 1 video 2 post to forum
calculator

Explanation:

Step1: Substitute $x=-2$ into $f(x)$

$f(-2)=3(-2)^2 -8(-2)+1$
$=3(4)+16+1=12+16+1$

Step2: Substitute $x=-1$ into $f(x)$

$f(-1)=3(-1)^2 -8(-1)+1$
$=3(1)+8+1=3+8+1$

Step3: Substitute $x=0$ into $f(x)$

$f(0)=3(0)^2 -8(0)+1$
$=0-0+1$

Step4: Substitute $x=1$ into $f(x)$

$f(1)=3(1)^2 -8(1)+1$
$=3(1)-8+1=3-8+1$

Step5: Substitute $x=2$ into $f(x)$

$f(2)=3(2)^2 -8(2)+1$
$=3(4)-16+1=12-16+1$

Answer:

$f(-2)=29$
$f(-1)=12$
$f(0)=1$
$f(1)=-4$
$f(2)=-3$