Question

given the system of equations:
x + 5y = 1
2x - 3y = 2
is (6, -1) a solution?
no
yes

Explanation:

Step1: Check first equation

Substitute \(x = 6\), \(y=-1\) into \(x + 5y = 1\).
Left side: \(6+5\times(-1)=6 - 5 = 1\), which equals the right side.

Step2: Check second equation

Substitute \(x = 6\), \(y = -1\) into \(2x-3y = 2\).
Left side: \(2\times6-3\times(-1)=12 + 3 = 15\), which is not equal to the right side (\(2\)).
Since the pair does not satisfy both equations, it is not a solution.

Answer:

No