Question

graph these equations:
$y = \frac{1}{2}x + 1$
$y = \frac{1}{2}x + 9$
click to select points on the graph.

Explanation:

Step1: Identify slope-intercept form

Both equations use $y=mx+b$, where $m=\frac{1}{2}$ (slope), $b$ = y-intercept.

Step2: Find points for $y=\frac{1}{2}x+1$

• When $x=0$: $y=\frac{1}{2}(0)+1=1$, point $(0,1)$
• When $x=2$: $y=\frac{1}{2}(2)+1=2$, point $(2,2)$

Step3: Find points for $y=\frac{1}{2}x+9$

• When $x=0$: $y=\frac{1}{2}(0)+9=9$, point $(0,9)$
• When $x=2$: $y=\frac{1}{2}(2)+9=10$, point $(2,10)$

Step4: Plot and connect points

Draw a line through $(0,1)$ & $(2,2)$; draw a line through $(0,9)$ & $(2,10)$.

Answer:

• For $y=\frac{1}{2}x+1$: Plot points $(0,1)$ and $(2,2)$, then draw a straight line through them.
• For $y=\frac{1}{2}x+9$: Plot points $(0,9)$ and $(2,10)$, then draw a straight line through them.

(The two lines are parallel, with the first line lower on the coordinate plane and the second line higher.)