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haley used 0.6 kilograms of raisins to make 52 bags of trail mix. to th…

Question

haley used 0.6 kilograms of raisins to make 52 bags of trail mix. to the nearest hundredth of a kilogram, how many kilograms of raisins, on average, did she put in each bag? kilograms

Explanation:

Step1: Identify the operation

To find the average amount of raisins per bag, we divide the total amount of raisins by the number of bags. So we use the formula: $\text{Average per bag} = \frac{\text{Total raisins}}{\text{Number of bags}}$.

Step2: Perform the division

We know the total raisins is $0.6$ kilograms and the number of bags is $52$. So we calculate $0.6\div52$.
$$0.6\div52 = \frac{0.6}{52}\approx0.011538$$

Step3: Round to the nearest hundredth

To round to the nearest hundredth, we look at the thousandth place. The number is $0.011538$, the thousandth digit is $1$. Since $1<5$, we round down. So $0.011538\approx0.01$ (wait, no, wait: wait, $0.6\div52 = 0.011538\cdots$. Wait, hundredth place is the second decimal. So the number is $0.01$ (first decimal 0, second 1, third 1). Wait, no, let's do the division correctly. $0.6\div52$: $52$ goes into $0.6$ zero times. Add a decimal point, $52$ goes into $6.0$ zero times (since $52>6$), $52$ goes into $60.0$ once (152 = 52), subtract 52 from 60, get 8. Bring down a 0: 80. $52$ goes into 80 once (152=52), subtract 52 from 80, get 28. Bring down a 0: 280. $52$ goes into 280 five times (552=260), subtract 260 from 280, get 20. Bring down a 0: 200. $52$ goes into 200 three times (352=156), subtract 156 from 200, get 44. Bring down a 0: 440. $52$ goes into 440 eight times (852=416), subtract 416 from 440, get 24. So putting it together, $0.6\div52 = 0.01153846\cdots$. Now, to the nearest hundredth: the hundredth digit is 1 (second decimal), the thousandth digit is 1 (third decimal). Wait, no: 0.01 (first decimal 0, second 1, third 1). Wait, no, decimal places: first decimal: tenths (0), second: hundredths (1), third: thousandths (1). So when rounding to the nearest hundredth, we look at the thousandth place (1). Since 1 < 5, we keep the hundredth place as is. Wait, but wait, maybe I made a mistake. Wait, $0.6\div52$: let's use a calculator. $0.6\div52 = 0.0115384615\cdots$. So to the nearest hundredth: the number is 0.01 (because the third decimal is 1, which is less than 5, so we round the hundredth place down? Wait, no: the number is 0.0115... So the tenths place is 0, hundredths is 1, thousandths is 1. So when rounding to the nearest hundredth, we look at the thousandth digit (1). Since 1 < 5, we leave the hundredth digit as is. So 0.01? Wait, that can't be right. Wait, no, wait: 0.6 divided by 52. Let's check: 520.01 = 0.52, which is less than 0.6. 520.011 = 0.572, 520.0115 = 0.598, 520.0116 = 0.6032. Oh! Wait, I see my mistake. So 0.6 divided by 52: 520.0115 = 0.598, 520.0116 = 0.6032. So 0.6 is between 520.0115 and 52*0.0116. So 0.6/52 = 0.011538... So to the nearest hundredth, we look at the thousandth place (1) and the hundredth place is 1. Wait, no, the decimal is 0.011538... So the first decimal: 0 (tenths), second: 1 (hundredths), third: 1 (thousandths), fourth: 5 (ten - thousandths). Wait, I messed up the decimal places. Let's write 0.6 as 0.600000. Then divide by 52:

52 ) 0.600000 ( 0.011538...
0
----
60
52
----
80
52
----
280
260
----
200
156
----
440
416
----
240
208
----
320
260
----
60

So the decimal is 0.01153846... So the tenths place: 0, hundredths: 1, thousandths: 1, ten - thousandths: 5. Wait, no: the first digit after decimal is tenths (0), second is hundredths (1), third is thousandths (1), fourth is ten - thousandths (5). So when rounding to the nearest hundredth, we look at the thousandth dig…

Answer:

0.01