Question

the height of an object tossed upward with an initial velocity of 96 feet per second is given by the formula h = -16t² + 96t, where h is the height in feet and t is the time in seconds. find the time required for the object to return to its point of departure. round to 1 decimal place, if necessary. seconds question help: ebook written example

Explanation:

Step1: Set height to zero

When the object returns to its point - of - departure, $h = 0$. So we set the equation $-16t^{2}+96t = 0$.

Step2: Factor out the common factor

Factor out $-16t$ from the left - hand side of the equation: $-16t(t - 6)=0$.

Step3: Solve for t

Using the zero - product property, if $ab = 0$, then either $a = 0$ or $b = 0$.
For $-16t=0$, we get $t = 0$ (this represents the initial time when the object is tossed).
For $t - 6=0$, we get $t = 6$.

Answer:

6.0