Question

how many grams are in 5.43 moles of no. 9? input the numeric value here. 1. sn₃n₄ 2. ca₃n₂ 3. agcl₃ 4. scl₆ 5. as₂s₃ 6. w₂o₃ 7. mn₂o₃ 8. na₂s 9. b₂s₃ 10. sro₂ 11. cubr₃ 12. sif₄ 13. rb₂s 14. mos₂ 15. c₃p₄ 16. crcl₃ 17. b₂o₃ 18. ge₃p₄ 19. sebr₆ 20. ca₃p₂ 21. al₂s₃ 22. ge₃n₄ 23. ncl₃ 24. pcl₅ 25. k₂co₃ 26. lino₃ 27. ni₂so₄ 28. na₂so₄ 29. cs₂so₄ 30. baco₃ 31. gapo₄ 32. cs₂so₄ 33. k₃po₄ 34. k₂so₄ 35. srso₄ 36. kno₃ 37. rbno₃ 38. csno₃ 39. b₂(co₃)₃ 40. ga(no₃)₃ 41. mg₃(po₄)₂ 42. ga₂(co₃)₃ 43. al(no₃)₃ 44. mn₂(so₄)₃ 45. ba₃(po₄)₂ 46. al₂(so₄)₃ 47. mn(co₃)₃ 48. b(no₃)₃ 49. ba₃(po₄)₂ 50. ca(no₃)₂ 51. cu(no₃)₂ 52. b₂(so₄)₃ 53. mn(no₃)₄ 54. cu(no₃)₂ 55. ca₃(po₄)₂ 56. ga(no₃)₃ 57. sn(no₃)₂ 58. mo(no₃)₃ 59. be₃(po₄)₂ 60. sr₃(po₄)₂ this problem can be solved by dimensional analysis as the primary method, formula where permitted, or simple math. using ratio and proportion methods is not allowed. be sure to show the formula on homework and exams. show work here as a file upload in the last question. be sure to report the units for all values when showing your work. keys will be posted for exemplary practice problems. you must show work on the exams. practice showing the calculator answer and the sig figs answer.

Explanation:

Step1: Calculate molar mass of $B_2S_3$

The molar mass of B is approximately 10.81 g/mol and of S is approximately 32.07 g/mol. For $B_2S_3$, molar mass $M=(2\times10.81 + 3\times32.07)$ g/mol$=(21.62+96.21)$ g/mol = 117.83 g/mol.

Step2: Use the formula $m = n\times M$

We know $n = 5.43$ moles and $M=117.83$ g/mol. So $m=5.43\times117.83$ g.
$m = 5.43\times117.83=639.8169$ g. Rounding to 3 significant - figures, $m = 640$ g.

Answer:

640