Question

how many moles of c₂h₄ are needed to form 0.92 mol of co₂? 0.46 mol c₂h₄

Explanation:

Step1: Write the balanced reaction

The combustion reaction of \( \ce{C2H4} \) is \( \ce{C2H4 + 3O2 -> 2CO2 + 2H2O} \) (assuming the product is \( \ce{CO2} \) as there is a typo and it should be \( \ce{CO2} \) instead of \( \ce{CO} \) otherwise the reaction will not be balanced properly. If we consider the reaction for \( \ce{CO} \) formation: \( \ce{C2H4 + 2O2 -> 2CO + 2H2O} \))

From the reaction \( \ce{C2H4 + 2O2 -> 2CO + 2H2O} \), the mole ratio of \( \ce{C2H4} \) to \( \ce{CO} \) is \( 1:2 \)

Step2: Calculate moles of \( \ce{C2H4} \)

Given moles of \( \ce{CO} = 0.92 \) mol

Let moles of \( \ce{C2H4} = x \)

Using mole ratio \( \frac{x}{0.92} = \frac{1}{2} \)

\( x=\frac{0.92}{2} = 0.46 \) mol

Answer:

\( 0.46 \) mol