Question

how many moles of sulfur trioxide are formed from 5 moles of sulfur dioxide using the given balanced equation?
2 so₂ + o₂ → 2 so₃
1 mol of so₃
2 mol of so₃
3 mol of so₃
5 mol of so₃
6 mol of so₃

Explanation:

Step1: Analyze the balanced equation

The balanced chemical equation is \(2\text{SO}_2 + \text{O}_2
ightarrow 2\text{SO}_3\). From this equation, we can see that the mole ratio of \(\text{SO}_2\) to \(\text{SO}_3\) is \(2:2\) (or simplified to \(1:1\)).

Step2: Use the mole ratio to calculate moles of \(\text{SO}_3\)

We are given 5 moles of \(\text{SO}_2\). Let \(x\) be the moles of \(\text{SO}_3\) formed. Using the mole ratio \(\frac{\text{moles of } \text{SO}_2}{\text{moles of } \text{SO}_3}=\frac{2}{2} = 1\), we can set up the proportion \(\frac{5}{x}=\frac{2}{2}\). Cross - multiplying gives \(2x = 5\times2\), so \(x = 5\) moles.

Answer:

5 mol of \(SO_3\) (the option: 5 mol of \(SO_3\))