Question

1. how many protons, neutrons and electrons are in this element? 10. label this electromagnetic spectrum (get all seven!) 11. (circle the right answer!) the relationship between wavelength and frequency is (direct/indirect) and the relationship between frequency and energy is (direct/indirect)? 12. youre wearing your goggles and apron when you bravely approach the bunsen burner and spray cucl₂ at the flame. it burns green at a wavelength of 505nm. how much energy did the photons emit? (be careful with formulas!)

Explanation:

Step1: Determine number of protons

The atomic number is 9, so number of protons = 9.

Step2: Calculate number of neutrons

Mass - number is 19, number of neutrons = mass - number - atomic number = 19 - 9 = 10.

Step3: Determine number of electrons

The ion has a 1 - charge, so number of electrons = atomic number+1 = 9 + 1=10.

for question 10:
The seven parts of the electromagnetic spectrum are radio waves, microwaves, infrared, visible light, ultraviolet, X - rays, and gamma rays.

for question 11:
The relationship between wavelength ($\lambda$) and frequency ($
u$) is given by $c=\lambda
u$ (where $c$ is the speed of light), so it is indirect. The relationship between frequency and energy ($E$) is given by $E = h
u$ (where $h$ is Planck's constant), so it is direct.

for question 12:
First, use the formula $c=\lambda
u$ to find frequency $
u=\frac{c}{\lambda}$. Given $c = 3\times10^{8}\ m/s$ and $\lambda=505\times10^{-9}\ m$. Then $
u=\frac{3\times10^{8}}{505\times10^{-9}}\ Hz$. Then use $E = h
u$, with $h = 6.63\times10^{-34}\ J\cdot s$.

Step1: Calculate frequency

$
u=\frac{3\times10^{8}}{505\times10^{-9}}\approx5.94\times10^{14}\ Hz$

Step2: Calculate energy

$E=h
u=6.63\times10^{-34}\times5.94\times10^{14}\ J\approx3.94\times10^{-19}\ J$

Answer:

Protons: 9, Neutrons: 10, Electrons: 10