how many real - number solutions does the equation (x^{2}+12 = 0) have?…

$how many real - number solutions does the equation (x^{2}+12 = 0) have?…$

how many real - number solutions does the equation (x^{2}+12 = 0) have?
options: 2, 3, 4, none

$x^2 = -12$

For all real $x$, $x^2 \geq 0$

$-12 < 0$, so no real $x$ satisfies $x^2=-12$

none