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hydrogen peroxide can be used to disinfect and clean surfaces around th…

Question

hydrogen peroxide can be used to disinfect and clean surfaces around the home. it breaks down over time into oxygen gas and water. consider the following reaction: some amount of hydrogen peroxide (h₂o₂) breaks down to produce 2 molecules of oxygen (o₂) and 4 molecules of water (h₂o). complete the table below. chemical element | number of atoms in the reaction h | o | during this reaction, how many molecules of hydrogen peroxide (h₂o₂) react?

Explanation:

Response
Part 1: Completing the table for number of atoms
For Hydrogen (H):

Step 1: Calculate H from water

Each water molecule ($\ce{H2O}$) has 2 H atoms, and there are 4 water molecules. So H from water: $4 \times 2 = 8$.
Hydrogen peroxide is the only other source, but let's check conservation. Wait, actually, in the products, water has H. So total H atoms: from 4 $\ce{H2O}$: $4\times2 = 8$.

Step 2: Confirm (no other H sources), so total H atoms = 8.

For Oxygen (O):

Step 1: Calculate O from oxygen gas

Each $\ce{O2}$ molecule has 2 O atoms, 2 molecules: $2\times2 = 4$.

Step 2: Calculate O from water

Each $\ce{H2O}$ has 1 O atom, 4 molecules: $4\times1 = 4$.

Step 3: Total O atoms: $4 + 4 = 8$.

Part 2: Number of $\ce{H2O2}$ molecules reacting

Step 1: Use conservation of H

Each $\ce{H2O2}$ has 2 H atoms. Let $n$ be the number of $\ce{H2O2}$ molecules. Total H from reactants: $2n$. From products (water), total H is 8 (from part 1). So $2n = 8$ → $n = 4$? Wait, no, wait. Wait, products: 4 $\ce{H2O}$ (each has 2 H) → 8 H. Reactants: $\ce{H2O2}$ has 2 H per molecule. So $2n = 8$ → $n = 4$? Wait, but let's check O.

Step 2: Use conservation of O

Each $\ce{H2O2}$ has 2 O atoms. So O from reactants: $2n$. From products: 2 $\ce{O2}$ (4 O) + 4 $\ce{H2O}$ (4 O) → 8 O. So $2n = 8$ → $n = 4$. Wait, but let's check the reaction equation. Wait, the products are 2 $\ce{O2}$ and 4 $\ce{H2O}$. Let's write the reaction:

$\ce{n H2O2 -> 2 O2 + 4 H2O}$

Balance H: left: 2n H; right: 4×2 = 8 H → 2n = 8 → n=4.

Balance O: left: 2n O; right: 2×2 + 4×1 = 8 O → 2n=8 → n=4. So n=4.

Answer:

s:

Table:
  • H: 8
  • O: 8
Number of $\ce{H2O2}$ molecules: 4