Question

identify the element and number of neutrons in atoms represented by the peak at 74 amu in the mass spectrum. stop the video and try this on your own.

Explanation:

Step1: Identify the element from mass number 74

First, we know that the mass number (A) is the sum of protons (Z) and neutrons (N), i.e., \( A = Z + N \). For an element, the atomic number (Z) is unique. Looking at common elements, the element with a mass number of 74 (and we can check the atomic number). The element with atomic number 32 is Germanium (Ge). The atomic number (Z) of Ge is 32.

Step2: Calculate the number of neutrons

Using the formula \( N = A - Z \), where \( A = 74 \) (mass number) and \( Z = 32 \) (atomic number of Ge). So, \( N = 74 - 32 = 42 \).

Answer:

The element is Germanium (Ge), and the number of neutrons in atoms represented by the peak at 74 amu is 42.