Question

(ii) 2x² + 9x + 10
a =
b =
c =

Explanation:

Assuming the quadratic expression is \(2x^{2}+9x + 10\) (correcting the hand - written notation), for a quadratic equation of the form \(ax^{2}+bx + c=0\) (or just the quadratic expression \(ax^{2}+bx + c\)):

Step 1: Identify the coefficient of \(x^{2}\)

In the expression \(2x^{2}+9x + 10\), the coefficient of \(x^{2}\) (the value of \(a\)) is the number multiplied by \(x^{2}\). So, \(a = 2\).

Step 2: Identify the coefficient of \(x\)

The coefficient of \(x\) (the value of \(b\)) is the number multiplied by \(x\). In \(2x^{2}+9x + 10\), the coefficient of \(x\) is \(9\), so \(b=9\).

Step 3: Identify the constant term

The constant term (the value of \(c\)) is the term without \(x\). In \(2x^{2}+9x + 10\), the constant term is \(10\), so \(c = 10\).

Answer:

\(a = 2\), \(b=9\), \(c = 10\)