Question

independent practice
linear equations
name: ____________________________ date: ____________
a. let us review first.

1. $4(2x + 3)$
2. $\frac{3x + 6}{3}$
3. $\frac{-2(3x - 6)}{-6}$

b. evaluate the given equations.

Explanation:

Step1: Distribute 4 to terms inside

$4(2x + 3) = 4\cdot2x + 4\cdot3$

Step2: Calculate the products

$= 8x + 12$

Step1: Split the fraction into two terms

$\frac{3x+6}{3} = \frac{3x}{3} + \frac{6}{3}$

Step2: Simplify each fraction

$= x + 2$

Step1: Distribute -2 to terms inside

$\frac{-2(3x-6)}{-6} = \frac{-6x + 12}{-6}$

Step2: Split the fraction into two terms

$= \frac{-6x}{-6} + \frac{12}{-6}$

Step3: Simplify each fraction

$= x - 2$

Answer:

1. $8x + 12$
2. $x + 2$
3. $x - 2$