Question

iron has a density of 7.86 g/cm³. the volume occupied by 55.85 g of iron is
○0.141 cm³.
○7.11 cm³.
○2.8 cm³.
○439 cm³.
○none of the above.

Explanation:

Step1: Recall the density formula

The formula for density is $
ho = \frac{m}{V}$, where $
ho$ is density, $m$ is mass, and $V$ is volume. We need to solve for volume, so rearrange the formula to $V=\frac{m}{
ho}$.

Step2: Substitute the given values

We know that $m = 55.85\space g$ and $
ho=7.86\space g/cm^{3}$. Substitute these values into the formula: $V=\frac{55.85}{7.86}$.

Step3: Calculate the result

Perform the division: $\frac{55.85}{7.86}\approx7.11\space cm^{3}$.

Answer:

7.11 $cm^{3}$ (corresponding to the option "7.11 $cm^{3}$")