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a jar contains 10 red marbles numbered 1 to 10 and 4 blue marbles numbe…

Question

a jar contains 10 red marbles numbered 1 to 10 and 4 blue marbles numbered 1 to 4. a marble is drawn at random from the jar. round your answer to four decimal places. find the probability that the a. marble is red: b. marble is odd - numbered: c. marble is red or blue: question help: video

Explanation:

Step1: Calculate total number of marbles

Total marbles = 10 (red) + 4 (blue)=14

Step2: Calculate probability of red marble

Number of red marbles = 10. Probability $P(\text{red})=\frac{\text{Number of red marbles}}{\text{Total number of marbles}}=\frac{10}{14}\approx0.7143$

Step3: Calculate number of odd - numbered marbles

Red odd - numbered marbles: 1, 3, 5, 7, 9 (5 marbles). Blue odd - numbered marbles: 1, 3 (2 marbles). Total odd - numbered marbles = 5 + 2=7. Probability $P(\text{odd})=\frac{\text{Number of odd - numbered marbles}}{\text{Total number of marbles}}=\frac{7}{14}=0.5000$

Step4: Calculate probability of red or blue marble

Since all marbles in the jar are either red or blue, the probability $P(\text{red or blue}) = 1.0000$

Answer:

a. 0.7143
b. 0.5000
c. 1.0000