Question

jared takes a 7-inch by 6-inch rectangle of fabric and cuts from one corner of the piece of fabric to the diagonally opposite corner. now jared has two equally sized triangles of fabric. what is the perimeter of each triangle? if necessary, round to the nearest tenth. inches submit

Explanation:

Step1: Identify triangle sides

The triangle has legs 7 inches and 6 inches.

Step2: Calculate diagonal (hypotenuse)

Use Pythagorean theorem: $c = \sqrt{a^2 + b^2} = \sqrt{7^2 + 6^2} = \sqrt{49 + 36} = \sqrt{85} \approx 9.22$ inches

Step3: Compute perimeter

Add all sides: $7 + 6 + 9.22 = 22.22$? Wait correction: Wait no, wait 7+6 is 13 plus ~9.2 is 22.2? Wait wait $\sqrt{85}$ is approx 9.2195 so 7+6+9.2195≈22.2195≈22.2 inches? Wait wait I miscalculated earlier: 7+6=13 +9.2=22.2 yes. So final perimeter≈22.2 inches.
Wait correction again: The correct hypotenuse is √(7²+6²)=√(49+36)=√85≈9.22. Then perimeter=7+6+9.22=22.22≈22.2 inches.

Step1: List triangle legs

Legs: 7 inches, 6 inches

Step2: Find hypotenuse length

$c = \sqrt{7^2 + 6^2} = \sqrt{85} \approx 9.22$ inches

Step3: Calculate perimeter

$7 + 6 + 9.22 = 22.22 \approx 22.2$ inches

Answer:

20.2 inches