Question

john dilutes some 6% (or 1.76 m) h₂o₂ to 3% (or 0.88 m) in order to create some disinfectant for a wound. what volume of the 1.76 m h₂o₂ does he need to make 300. ml of the 0.88 m solution? ? ml of 1.76 m h₂o₂

Explanation:

Step1: Recall the dilution formula

The dilution formula is \( M_1V_1 = M_2V_2 \), where \( M_1 \) is the initial molarity, \( V_1 \) is the initial volume, \( M_2 \) is the final molarity, and \( V_2 \) is the final volume.

Step2: Identify the known values

We know that \( M_1 = 1.76 \, \text{M} \), \( M_2 = 0.88 \, \text{M} \), and \( V_2 = 300. \, \text{mL} \). We need to find \( V_1 \).

Step3: Rearrange the formula to solve for \( V_1 \)

From \( M_1V_1 = M_2V_2 \), we can rearrange to get \( V_1=\frac{M_2V_2}{M_1} \).

Step4: Substitute the known values into the formula

Substitute \( M_2 = 0.88 \, \text{M} \), \( V_2 = 300. \, \text{mL} \), and \( M_1 = 1.76 \, \text{M} \) into the formula:
\( V_1=\frac{0.88 \, \text{M} \times 300. \, \text{mL}}{1.76 \, \text{M}} \)
First, calculate the numerator: \( 0.88 \times 300 = 264 \)
Then, divide by the denominator: \( \frac{264}{1.76}=150 \)
So, \( V_1 = 150 \, \text{mL} \)

Answer:

150