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Question
- kelsey swims 1.5km east, then bikes 40km north, and then runs 10km west. based on the properties that define vector quantities in two - dimensional motion, which choice gives the correct solution for the magnitude of kelseys displacement? clear all c²=(40²)+(10²) c²=(1.5²)+(40²) c²=(40²)+(10²)+(1.5²) c²=(40²)+(8.5²)
Step1: Analyze displacements
The east - west displacements are $1.5$ km east and $10$ km west. The net east - west displacement is $10 - 1.5=8.5$ km west. The north - south displacement is $40$ km north.
Step2: Apply Pythagorean theorem
For a right - triangle formed by the net east - west and north - south displacements, if the magnitude of the displacement is $C$, then by the Pythagorean theorem $C^{2}=(40^{2})+(8.5^{2})$.
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$C^{2}=(40^{2})+(8.5^{2})$