Question

let $f(x)=3x^{2}+4$ and $g(x)= - 3x+6$. find the following.
$(f - g)(-4)$

$(f - g)(-4)=\square$

Explanation:

Step1: Define $(f-g)(x)$

$(f-g)(x) = f(x) - g(x) = (3x^2 + 4) - (-3x + 6)$

Step2: Simplify the expression

$(f-g)(x) = 3x^2 + 4 + 3x - 6 = 3x^2 + 3x - 2$

Step3: Substitute $x=-4$

$(f-g)(-4) = 3(-4)^2 + 3(-4) - 2$

Step4: Calculate each term

$3(-4)^2 = 3\times16 = 48$, $3(-4) = -12$

Step5: Combine terms

$(f-g)(-4) = 48 - 12 - 2$

Answer:

34