Question

let $f(x)=x^2$ and $g(x)=x-6$. find $(f \circ g)(-4)$.

$(f \circ g)(-4)=\square$ (simplify your answer.)

Explanation:

Step1: Calculate $g(-4)$

$g(-4) = -4 - 6 = -10$

Step2: Substitute into $f(x)$

$f(g(-4)) = f(-10) = (-10)^2$

Step3: Compute the final value

$(-10)^2 = 100$

Answer:

100