Question

1. lin and han’s families provide money for their school lunch accounts.

• han starts with $100 in his account. he spends $15 each week on lunches.
• lin starts with $25 in her account and does not spend any of it. her family adds $10 each week to her account.

a. at the end of 4 weeks, who has more money in their account?

b. after how many weeks will han and lin have the same amount of money in their lunch accounts?

problem 7
a. a farm has chickens and cows. all the cows have 4 legs and all the chickens have 2 legs. all together, there are 82 cow and chicken legs on the farm. complete the table to show some possible combinations of chickens and cows to get 82 total legs.

number of chickens (x)	number of cows (y)
7
	10
19
	5

Explanation:

Part 6a:

Step1: Calculate Han's balance after 4 weeks

Han starts with $100 and spends $15 per week. So the formula for his balance \( H \) after \( w \) weeks is \( H = 100 - 15w \). For \( w = 4 \):
\( H = 100 - 15\times4 = 100 - 60 = 40 \) dollars.

Step2: Calculate Lin's balance after 4 weeks

Lin starts with $25 and gets $10 per week. The formula for her balance \( L \) after \( w \) weeks is \( L = 25 + 10w \). For \( w = 4 \):
\( L = 25 + 10\times4 = 25 + 40 = 65 \) dollars.

Step3: Compare the two balances

Since \( 65 > 40 \), Lin has more money.

Step1: Set up the equation

Let \( w \) be the number of weeks. Han's balance: \( 100 - 15w \). Lin's balance: \( 25 + 10w \). Set them equal:
\( 100 - 15w = 25 + 10w \)

Step2: Solve for \( w \)

Add \( 15w \) to both sides:
\( 100 = 25 + 25w \)

Subtract 25 from both sides:
\( 75 = 25w \)

Divide both sides by 25:
\( w = \frac{75}{25} = 3 \)

Answer:

Lin has more money in her account at the end of 4 weeks.

Part 6b: