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solve $\log(3x - 5) = 2$.
the solution is $x = \square$.
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Step1: Convert log to exponential form
Since $\log$ is base 10, $\log(3x-5)=2$ becomes $10^2 = 3x - 5$
Step2: Calculate $10^2$
$100 = 3x - 5$
Step3: Isolate the term with $x$
Add 5 to both sides: $100 + 5 = 3x$
$105 = 3x$
Step4: Solve for $x$
Divide by 3: $x = \frac{105}{3}$
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