QUESTION IMAGE
Question
do the math
compare reactants and products
in a chemical reaction, bonds are broken and formed as atoms are rearranged to produce new substances. you can analyze the equation for cellular respiration to see how the reactants are rearranged to form the products.
- count the number
of each type of atom
in the reactants and
products of cellular
respiration. use
the diagram and
text about cellular
respiration to help you.
| type of atom | number of atoms in reactants | number of atoms in products |
|---|---|---|
| hydrogen (h) | ||
| oxygen (o) |
To solve this, we use the cellular respiration equation: \( \ce{C6H12O6 + 6O2 -> 6CO2 + 6H2O} \) (glucose + oxygen → carbon dioxide + water).
Step 1: Count Carbon (C) atoms
- Reactants: Glucose (\( \ce{C6H12O6} \)) has 6 C atoms; \( \ce{O2} \) has 0. Total: \( 6 + 0 = 6 \).
- Products: \( \ce{6CO2} \) has \( 6 \times 1 = 6 \) C atoms.
Step 2: Count Hydrogen (H) atoms
- Reactants: Glucose (\( \ce{C6H12O6} \)) has 12 H atoms; \( \ce{O2} \) has 0. Total: \( 12 + 0 = 12 \).
- Products: \( \ce{6H2O} \) has \( 6 \times 2 = 12 \) H atoms.
Step 3: Count Oxygen (O) atoms
- Reactants: Glucose (\( \ce{C6H12O6} \)) has 6 O atoms; \( \ce{6O2} \) has \( 6 \times 2 = 12 \). Total: \( 6 + 12 = 18 \).
- Products: \( \ce{6CO2} \) has \( 6 \times 2 = 12 \) O atoms; \( \ce{6H2O} \) has \( 6 \times 1 = 6 \). Total: \( 12 + 6 = 18 \).
| Type of Atom | Number in Reactants | Number in Products |
|---|---|---|
| Hydrogen (H) | 12 | 12 |
| Oxygen (O) | 18 | 18 |
This shows the law of conservation of mass: atoms are rearranged, not created or destroyed.
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| Type of Atom | Number in Reactants | Number in Products |
|---|---|---|
| Hydrogen (H) | 12 | 12 |
| Oxygen (O) | 18 | 18 |