Question

1. $2sqrt3{x}-6 = 18$

Explanation:

Step1: Isolate the radical term

Add 6 to both sides.
$$2\sqrt[3]{x} = 18 + 6$$
$$2\sqrt[3]{x} = 24$$

Step2: Solve for the cube root

Divide both sides by 2.
$$\sqrt[3]{x} = \frac{24}{2}$$
$$\sqrt[3]{x} = 12$$

Step3: Eliminate the cube root

Cube both sides of the equation.
$$x = 12^3$$
$$x = 1728$$

Answer:

$x = 1728$