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Question
- $(2v^{-9})^{10}$
Step1: Apply power of a product rule
$(ab)^n = a^n b^n$, so $(2v^{-9})^{10}=2^{10} \cdot (v^{-9})^{10}$
Step2: Calculate $2^{10}$
$2^{10}=1024$
Step3: Apply power of a power rule
$(a^m)^n=a^{m \cdot n}$, so $(v^{-9})^{10}=v^{-9 \times 10}=v^{-90}$
Step4: Rewrite positive exponent (optional)
$v^{-90}=\frac{1}{v^{90}}$
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$1024v^{-90}$ or $\frac{1024}{v^{90}}$