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Question
- $sqrt3{\frac{125}{64}}$
Step1: Recall cube - root property
$\sqrt[3]{\frac{a}{b}}=\frac{\sqrt[3]{a}}{\sqrt[3]{b}}$, where $a = 125$ and $b = 64$.
Step2: Find cube - root of 125
Since $5\times5\times5=125$, $\sqrt[3]{125}=5$.
Step3: Find cube - root of 64
Since $4\times4\times4 = 64$, $\sqrt[3]{64}=4$.
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$\frac{5}{4}$