Question

1. \\(k^{-4}j^{0}\\)

Explanation:

Step1: Recall exponent rules

Any non - zero number to the power of 0 is 1, so \(j^{0}=1\) (assuming \(j
eq0\)). Also, the negative exponent rule states that \(a^{-n}=\frac{1}{a^{n}}\) for \(a
eq0\) and \(n\) is a positive integer.

Step2: Simplify the expression

We have \(k^{-4}j^{0}\). Substitute \(j^{0} = 1\) into the expression, we get \(k^{-4}\times1=k^{-4}\). Then, using the negative exponent rule, \(k^{-4}=\frac{1}{k^{4}}\).

Answer:

\(\frac{1}{k^{4}}\) (assuming \(k
eq0\) and \(j
eq0\))