$7.1663 = 5\\ln(y)$ $1.4333 = \\ln(y)$ $y = \\square$

$7.1663 = 5\ln(y)$
$1.4333 = \ln(y)$
$y = \square$

Apply exponential to both sides: $e^{\ln(y)} = e^{1.4333}$

Use $e^{\ln(y)}=y$, so $y = e^{1.4333}$

Compute the exponential: $y \approx e^{1.4333}$

$y \approx 4.19$